Integrand size = 26, antiderivative size = 86 \[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\frac {i 2^{-1+\frac {m}{2}} \operatorname {Hypergeometric2F1}\left (2-\frac {m}{2},\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{-m/2}}{a d m} \]
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Time = 0.19 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3586, 3604, 72, 71} \[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\frac {i 2^{\frac {m}{2}-1} (1+i \tan (c+d x))^{-m/2} (e \sec (c+d x))^m \operatorname {Hypergeometric2F1}\left (2-\frac {m}{2},\frac {m}{2},\frac {m+2}{2},\frac {1}{2} (1-i \tan (c+d x))\right )}{a d m} \]
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Rule 71
Rule 72
Rule 3586
Rule 3604
Rubi steps \begin{align*} \text {integral}& = \left ((e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \int (a-i a \tan (c+d x))^{m/2} (a+i a \tan (c+d x))^{-1+\frac {m}{2}} \, dx \\ & = \frac {\left (a^2 (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \text {Subst}\left (\int (a-i a x)^{-1+\frac {m}{2}} (a+i a x)^{-2+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {\left (2^{-2+\frac {m}{2}} (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} \left (\frac {a+i a \tan (c+d x)}{a}\right )^{-m/2}\right ) \text {Subst}\left (\int \left (\frac {1}{2}+\frac {i x}{2}\right )^{-2+\frac {m}{2}} (a-i a x)^{-1+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {i 2^{-1+\frac {m}{2}} \operatorname {Hypergeometric2F1}\left (2-\frac {m}{2},\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{-m/2}}{a d m} \\ \end{align*}
Time = 2.05 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.77 \[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=-\frac {i 2^{-1+m} e^{-i (c+2 d x)} \left (\frac {e^{i (c+d x)}}{1+e^{2 i (c+d x)}}\right )^m \left (1+e^{2 i (c+d x)}\right )^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (-2+m),-1+m,\frac {m}{2},-e^{2 i (c+d x)}\right ) \sec ^{1-m}(c+d x) (e \sec (c+d x))^m (\cos (d x)+i \sin (d x))}{d (-2+m) (a+i a \tan (c+d x))} \]
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\[\int \frac {\left (e \sec \left (d x +c \right )\right )^{m}}{a +i a \tan \left (d x +c \right )}d x\]
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\[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\int { \frac {\left (e \sec \left (d x + c\right )\right )^{m}}{i \, a \tan \left (d x + c\right ) + a} \,d x } \]
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\[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=- \frac {i \int \frac {\left (e \sec {\left (c + d x \right )}\right )^{m}}{\tan {\left (c + d x \right )} - i}\, dx}{a} \]
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Exception generated. \[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\text {Exception raised: RuntimeError} \]
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\[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\int { \frac {\left (e \sec \left (d x + c\right )\right )^{m}}{i \, a \tan \left (d x + c\right ) + a} \,d x } \]
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Timed out. \[ \int \frac {(e \sec (c+d x))^m}{a+i a \tan (c+d x)} \, dx=\int \frac {{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^m}{a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}} \,d x \]
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